Carboxylic Acid Derivatives Question 2

Question 2 - 25 January - Shift 1

The correct sequence of reagents for the preparation of $Q$ and $R$ is :

(1) (i) $Cr_2 O_3, 770 $ $K, 20$ $ atm$;
(ii) $CrO_2 Cl_2, H_3 O^{+}$;
(iii) $NaOH$;
(iv) $H_3 O^{+}$

(2) (i) $CrO_2 Cl_2, H_3 O^{+}$;
(ii) $Cr_2 O_3, 770$ $ K, 20$ $ atm$;
(iii) $NaOH$;
(iv) $H_3 O^{+}$

(3) (i) $KMnO_4, OH^{-}$;
(ii) $Mo_2 O_3, A$;
(iii) $NaOH$;
(iv) $H_3 O^{+}$

(4) (i) $Mo_2 O_3, \Delta$;
(ii) $CrO_2 Cl_2, H_3 O^{+}$;
(iii) $NaOH$;
(iv) $H_3 O^{+}$

Show Answer

Answer: (1)

Solution:

Formula: Cannizzaro Reaction