JEE Main 12 Jan 2019 Morning Question 25
Question: An ideal gas occupies a volume of $ 2m^{3} $ at a pressure of $ 3\times 10^{6}Pa $ . The energy of the gas is [JEE Main Online Paper Held On 12-Jan-2019 Morning]
Options:
A) $ 9\times 10^{6}J $
B) $ 3\times 10^{2}J $
C) $ 6\times 10^{4}J $
D) $ 10^{8}J $
Show Answer
Answer:
Correct Answer: A
Solution:
We know that $ PV=\frac{2}{3}E $
$ E=\frac{3PV}{2}=3\times \frac{3\times 10^{6}}{2}\times 2=9\times 10^{6}J $
