JEE Main 12 Jan 2019 Morning Question 20
Question: The least count of the main scale of a screw gauge is 1 mm. The minimum number of divisions on its circular scale required to measure $ 5\mu m $ diameter of a wire is [JEE Main Online Paper Held On 12-Jan-2019 Morning]
Options:
A) 50
B) 100
C) 200
D) 500
Show Answer
Answer:
Correct Answer: C
Solution:
- Least count = 1 mm $ N _{d} $ (Number of divisions) $ =\frac{L.C.}{5\mu m} $ $ =\frac{1mm}{5\mu m}=\frac{10^{3}}{5}=200 $
