JEE Main 12 Jan 2019 Morning Question 18
Question: For the given cyclic process CAB as shown for a gas, the work done is [JEE Main Online Paper Held On 12-Jan-2019 Morning]
Options:
A) 10 J
B) 1 J
C) 5 J
D) 30 J
Show Answer
Answer:
Correct Answer: A
Solution:
- CA= change in volume $ \Delta V=(5-1)=4m^{3} $
$ AB= $ change in pressure $ \Delta P=(6-1)=5m^{3} $
Work done = Area of $ \Delta ABC=\frac{1}{2}\times AB\times CA $ $ W=\frac{1}{2}\times 4\times 5=10J $
