JEE Main 12 Jan 2019 Morning Question 20
Question: The volume of gas A is twice than that of gas B. The compressibility factor of gas A is thrice than that of gas B at same temperature. The pressures of the gases for equal number of moles are [JEE Main Online Paper Held On 12-Jan-2019 Morning]
Options:
A) $ 2P _{A}=3P _{B} $
B) $ 3P _{A}=2P _{B} $
C) $ P _{A}=2P _{B} $
D) $ P _{A}=3P _{B} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ Z _{A}=\frac{P _{A}V _{A}}{nRT _{A}},Z _{B}=\frac{P _{B}V _{B}}{nRT _{B}} $
Given, $ T _{A}=T _{B} $ n = same $ V _{A}=2V _{B} $ $ Z _{A}=3Z _{B} $
Then, $ Z _{A}=\frac{P _{A}\times 2V _{B}}{nRT _{A}}=3Z _{B}=\frac{3P _{B}V _{B}}{nRT _{B}} $ $ P _{A}\times 2V _{B}=3P _{B}V _{B},2P _{A}=3P _{B} $
