JEE Main 12 Jan 2019 Evening Question 28
Question: To double the covering range, or’ a TV transmission tower, its height should be multiplied by [JEE Main Online Paper Held On 12-Jan-2019 Evening]
Options:
A) $ \frac{1}{\sqrt{2}} $
B) 2
C) 4
D) $ \sqrt{2} $
Show Answer
Answer:
Correct Answer: C
Solution:
The distance to horizon, of the transmitting tower,
$d=\sqrt{2gh} $ $ \frac{d _2}{d _1}=\sqrt{\frac{h _2}{h _1}}\Rightarrow \frac{2d _1}{d _1}=\sqrt{\frac{h _2}{h _1}}\Rightarrow h _2=4h _1 $
