JEE Main On 08 April 2018 Question 6
Question: Two masses $ m _1=5kg $ and $ m _2=10kg $ , connected by an inextensible string over a frictionless pulley, are moving as shown in the figure. The coefficient of friction of horizontal surface is 0.15. The minimum weight m that should be put on top of $ m _2 $ to stop the motion is: [JEE Main Online 08-04-2018]
Options:
A) $ 43\text{.3 kg} $
B) $ 10\text{.3 kg} $
C) $ 18\text{.3 kg} $
D) $ 27\text{.3 kg} $
Show Answer
Answer:
Correct Answer: D
Solution:
- $ m _1g=\mu (m _2+m)g $
$ \therefore m=23.3kg $ Value greater than this and minimum in the given options is 27.3 kg
