JEE Main On 08 April 2018 Question 21

Options:

A) $ [3Ca _3{{(PO _4)}_2}\cdot CaF _2] $

B) $ [3{Ca{{(OH)}_2}}\cdot CaF _2] $

C) $ [CaF _2] $

D) $ [3(CaF _2)\cdot Ca{{(OH)}_2}] $

Show Answer

Answer:

Correct Answer: A

Solution:

  • The $ {F^{–}} $ ion makes the enamel on teeth much harder by converting hydroxyapatite $ [\text{ 3C}{a_3}{{\text{(P}{O_4}\text{)}}_2}\text{.Ca(OH}{{)}_2}] $ into much harder Fluor apatite $ [\text{ 3C}{a_3}{{\text{(P}{O_4}\text{)}}_2}\text{.Ca}{F_2}] $ .