JEE Main Solved Paper 2017 Question 6
Question: A diverging lens with magnitude of focal length 25 cm is placed at a distance of 15 cm from a converging lens of magnitude of focal length 20 cm. A beam of parallel light falls on the diverging lens. The final image formed is: [JEE Main Solved Paper-2017]
Options:
A) real and at a distance of 40 cm from the divergent lens
B) real and at a distance of 6 cm from the convergent lens
C) real and at a distance of 40 cm from convergent lens
D) virtual and at a distance of 40 cm from convergent lens. [JEE Main 2017]
Show Answer
Answer:
Correct Answer: C
Solution:
- As parallel beam incident on diverging lens if forms virtual image at $ v _1=-25,cm $ from the diverging lense which works as a object for the converging lense (f = 20 cm) So for converging lens $ u=-40cm,f=20,cm $
$ \therefore $ Finance image $ \frac{1}{V}-\frac{1}{-40}=\frac{1}{20} $ V = 40 cm from converging lenses.
