JEE Main Solved Paper 2017 Question 19
Question: In a coil of resistance $ 100,\Omega , $ a current is induced by changing the magnetic flux through it as shown in the figure. The magnitude of change in flux through the coil is: [JEE Main Solved Paper-2017]
Options:
A) 250 Wb
B) 275 Wb
C) 200 Wb
D) 225 Wb
Show Answer
Answer:
Correct Answer: A
Solution:
- $ q=\frac{\Delta o|}{R} $ $ \Delta \text{o }|= $ change in flux $ q=\int _{{}}^{{}}{I,dt} $ = Area of current-time graph $ =\frac{1}{2}\times 10\times 0.5=2.5 $ coloumb $ q=\frac{\Delta o|}{R} $ $ \Delta \text{o }|\text{ =2}\text{.5}\times 100=250,Wb $
