JEE Main Solved Paper 2017 Question 4
Question: The radius of the second Bohr orbit for hydrogen atom is: (Plank’s const. $ h,\text{=},6\text{.6262}\times 1{0^{-34}},Js; $ mass of electron $ =9.1091\times {10^{-31}},kg; $ charge of electron $ e=1.60210\times {10^{-19}}C; $ permittivity of vaccum $ {\in_0}=8.854185\times {10^{-12}},k{g^{-1}}{m^{-3}}A^{2}) $ [JEE Main Solved Paper-2017]
Options:
A) $ 1.65\overset{o}{\mathop{A}}, $
B) $ 4.76\overset{o}{\mathop{A}}, $
C) $ 0.529\overset{o}{\mathop{A}}, $
D) $ 212\overset{o}{\mathop{A}}, $
Show Answer
Answer:
Correct Answer: D
Solution:
- Radius of nth Bohr orbit in H-atom $ =0.53n^{2}\overset{o}{\mathop{A}}, $ Radius of II Bohr orbit $ =0.53\times {{(2)}^{2}} $ $ =2.12\overset{o}{\mathop{A}}, $
