JEE Main Solved Paper 2017 Question 29
Question: Given $ E _{Cl{ _2}/C{l^{-}}}^{0}=13.6,E _{C{r^{3+}}/Cr}^{0}=-0.74,V $ $ E _{Cr _2O_7^{2-}/C{r^{3+}}}^{0}=1.33V,E _{MnO_4^{-}/M{n^{2+}}}^{0}=1.51,V. $ Among the following, the strongest reducing agent is [JEE Main Solved Paper-2017]
Options:
A) Cr
B) $ M{n^{2+}} $
C) $ C{r^{3+}} $
D) $ C{l^{-}} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ E _{MnO_4^{-}/M{n^{+2}}}^{0}=1.51,V $ ..(i)
$ E _{Cl _2/C{l^{-}}}^{0}=1.36,V $ ..(ii)
$ E _{Cr _2O_7^{-2}/C{r^{+3}}}^{0}=1.33,V $ ..(iii)
$ E _{C{r^{+3}}/Cr}^{0}=-0.74 $ ..(iv)
Since $ C{r^{\text{+3}}} $ is having least reducing potential, so Cr is the best Reducing agent.
