JEE Main On 8 April 2017 Question 25
Question: The major product of the following reaction is: $ CH _3\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{C}},HCH _2\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{C}},CH _2CH _3\xrightarrow[heat]{KOH,CH _3OH} $ [JEE Online 08-04-2017]
Options:
A) $ CH _3CH=CH-CH=CHCH _3 $
B) $ CH _2=CHCH=CHCH _2CH _3 $
C) $ CH _2CH=C=CHCH _2CH _3 $
D) $ CH _2=CHCH _2CH=CHCH _3 $
Show Answer
Answer:
Correct Answer: A
Solution:
- Conjugated alkene in which double bonds are more substituted is the major product. When dibromoalkane is heated with $CH_3OH/KOH$, it undergoes dehydrohalogentation. Two molecules of HBr are eliminated to form alkadiene.
