Wave Motion 4 Question 1

1. Two sources of sound S1 and S2 produce sound waves of same frequency 660Hz. A listener is moving from source S1 towards S2 with a constant speed um/s and he hears 10 beats/s. The velocity of sound is 330m/s. Then, u equal to

(2019 Main, 12 April II)

(a) 5.5m/s

(b) 15.0m/s

(c) 2.5m/s

(d) 10.0m/s

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Answer:

Correct Answer: 1. (c)

Solution:

  1. When observer moves away from S1 and towards S2,

then due to Doppler’s effect observed frequencies of sources by observer are

fS1=vvovfS1

(observer moving away from source) and

fS2=(v+vov)fS2

(observer moving towards source)

(where, v= speed to sound, vo= speed of observer)

So, beat frequency heard by observer is

Here,

fb=fS2fS1vo=u,v=330ms1fb=10Hz,fS1=fS2=660Hz

On putting the values, we get

fb=fS2fS1=(v+vov)fS2(vvov)fS1=fS1v+vovvvov=fS12vov[vo=u]10=660×2u330u=2.5ms1



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