Wave Motion 3 Question 11

11. A uniform rope of length 12m and mass 6kg hangs vertically from a rigid support. A block of mass 2kg is attached to the

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Answer:

Correct Answer: 11. 0.12m

Solution:

  1. v=T/μ

vtop vbottom =Ttop Tbottom =6+22=2

Frequency will remain unchanged. Therefore, Eq. (i) can be written as,

fλtop fλbottom =2 or λtop =2(λbottom )=2×0.06=0.12m



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