Wave Motion 1 Question 8

8. A transverse wave is described by the equation y=y0sin2π(ftxλ). The maximum particle velocity is equal to four times the wave velocity if

(1984, 2M)

(a) λ=πy0/4

(b) λ=πy0/2

(c) λ=πy0

(d) λ=2πy0

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Answer:

Correct Answer: 8. (b)

Solution:

  1. Wave velocity v= coefficient of t coefficient of x=2πf2π/λ=λf

Maximum particle velocity vpm=ωA=2πfy0

Given,

vpm=4v

 or 2πfy0=4λfλ=πy02



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