SATHEE: Wave Motion 1 Question 14

Wave Motion 1 Question 14

14. The amplitude of a wave disturbance travelling in the positive $x$ -direction is given by $y = \frac{1}{(1 + x)^{2}}$ at time $t = 0$ and by $y = \frac{1}{[1 + (x - 1)^{2}]}$ at $t = 2 s$ , where $x$ and $y$ are in metre. The shape of the wave disturbance does not change during the propagation. The velocity of the wave is ….. $m / s$ .

(1990, 2M)

Show Answer

Answer:

Correct Answer: 14. $2 π v A, 4 π^{2} v^{2} A$

Solution:

In the question, it is given that the shape of the wave disturbance does not change, while in the opinion of author this is not true.

From the function, $y = \frac{1}{(1 + x)^{2}}$ , we can see that, at $x = - 1, y = \infty$ .

Whereas from the second function, $y = \frac{1}{[1 + (x - 1)^{2}]}$ we don’t get any point where $y = \infty$ .

So, how can we say that shape has not changed.

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Wave Motion 1 Question 14

14. The amplitude of a wave disturbance travelling in the positive x-direction is given by y=1(1+x)2 at time t=0 and by y=1[1+(x−1)2] at t=2s, where x and y are in metre. The shape of the wave disturbance does not change during the propagation. The velocity of the wave is ….. m/s.

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu