Simple Harmonic Motion 5 Question 1

1. A simple pendulum oscillating in air has period T. The bob of the pendulum is completely immersed in a non-viscous liquid. The density of the liquid is 116 th of the material of the bob. If the bob is inside liquid all the time, its period of oscillation in this liquid is

(a) 2T110

(b) 2T114

(c) 4T114

(d) 4T115

(Main 2019, 9 April I)

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Answer:

Correct Answer: 1. (d)

Solution:

  1. We know that,

Time period of a pendulum is given by

T=2πL/geff 

Here, L is the length of the pendulum and geff  is the effective acceleration due to gravity in the respective medium in which bob is oscillating.

Initially, when bob is oscillating in air, geff =g.

So, initial time period, T=2πLg

Let ρbob  be the density of the bob.

When this bob is dipped into a liquid whose density is given as

ρliquid =ρbob 16=ρ16

Net force on the bob is

Fnet =VρgVρ16g

(where, V= volume of the bob = volume of displaced liquid by the bob when immersed in it). If effective value of gravitational acceleration on the bob in this liquid is geff , then net force on the bob can also be written as

Fnet =Vρgeff 

Equating Eqs. (iii) and (iv), we have

Vρgeff =VρgVρg/16geff =gg/16=1516g

Substituting the value of geff  from Eq. (v) in Eq. (i), the new time period of the bob will be

T=2πLgeff =2π1615LgT=1615×2πLg=415×T [using Eq. (ii)] 



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