Simple Harmonic Motion 3 Question 10

10. A solid sphere of radius R is floating in a liquid of density ρ with half of its volume submerged. If the sphere is slightly pushed and released, it starts performing simple harmonic motion. Find the frequency of these oscillations.

(2004, 4M)

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Answer:

Correct Answer: 10. 12π3g2R

Solution:

  1. Half of the volume of sphere is submerged.

For equilibrium of sphere, weight = upthrust

Vρsg=V2(ρL)(g)ρs=ρL2

When slightly pushed downwards by x, weight will remain as it is while upthrust will increase. The increased upthrust will become the net restoring force (upwards).

F=( extra upthrust )=( extra volume immersed )(ρL)(g) or ma=(πR2)xρLg(a= acceleration )43πR3ρ2a=(πR2ρg)xa=3g2Rx

as ax, motion is simple harmonic.

Frequency of oscillation, f=12πax

=12π3g2R



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