Simple Harmonic Motion 2 Question 3

3. For a particle executing SHM the displacement x is given by x=Acosωt. Identify the graph which represents the variation of potential energy (PE) as a function of time t and displacement x.

(2003, 2M)

(a) I, III

(b) II, IV

(c) II, III

(d) I, IV

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Answer:

Correct Answer: 3. (a)

Solution:

  1. Potential energy is minimum (in this case zero) at mean position (x=0) and maximum at extreme positions (x=±A). At time t=0,x=A. Hence, PE should be maximum. Therefore, graph I is correct. Further in graph III, PE is minimum at x=0. Hence, this is also correct .


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