Simple Harmonic Motion 1 Question 7

7. An object of mass 0.2kg executes simple harmonic oscillations along the X-axis with a frequency of (25/π)Hz. At the position x=0.04, the object has kinetic energy of 0.5J and potential energy 0.4J. The amplitude of oscillations is …….m.

(1994, 2M)

Show Answer

Answer:

Correct Answer: 7. 0.06

Solution:

  1. Since, ν=12πkm

⇒25π=12πk0.2

or k=50×50×0.2=500N/m

If A is the amplitude of oscillation,

Total energy =KE+PE

12kA2=0.5+0.4A=2×0.9500=0.06m

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