Simple Harmonic Motion 1 Question 3

3. A particle is executing simple harmonic motion (SHM) of amplitude A, along the X-axis, about x=0. when its potential energy (PE) equals kinetic energy (KE), the position of the particle will be

(2019 Main, 9 Jan II)

(a) A

(b) A2

(c) A22

(d) A2

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Answer:

Correct Answer: 3. (d)

Solution:

  1. Here, A =amplitude of particle in SHM

We know that in SHM potential energy (U) of a particle is given by the relation at distance x from the mean position is

U=12kx2

and at the same point kinetic energy (K)

= Total energy  Potential energy =12kA212kx2

According to the question,

potential energy = kinetic energy

12kx2=12kA212kx2 or kx2=kA22 or x=±A2



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