Rotation 5 Question 17

29. When $\operatorname{disc} B$ is brought in contact with $\operatorname{disc} A$, they acquire a common angular velocity in time $t$. The average frictional torque on one disc by the other during this period is

(a) $\frac{2 I \omega}{3 t}$

(b) $\frac{9 I \omega}{2 t}$

(c) $\frac{9 I \omega}{4 t}$

(d) $\frac{3 I \omega}{2 t}$

(2007, 4M)

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Answer:

Correct Answer: 29. (a)

Solution:

  1. Let $\omega^{\prime}$ be the common velocity. Then from conservation of angular momentum, we have

$$ \begin{aligned} (I+2 I) \omega^{\prime} & =I(2 \omega)+2 I(\omega) \\ \omega^{\prime} & =\frac{4}{3} \omega \end{aligned} $$

From the equation,

angular impulse $=$ change in angular momentum, for any of the disc, we have

$$ \begin{aligned} \tau \cdot t & =I(2 \omega)-I \frac{4}{3} \omega=\frac{2 I \omega}{3} \\ \therefore \quad \tau & =\frac{2 I \omega}{3 t} \end{aligned} $$



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