Rotation 2 Question 1

1. The time dependence of the position of a particle of mass m=2 is given by r(t)=2ti^3t2j^. Its angular momentum, with respect to the origin, at time t=2 is

(a) 36k^

(b) 34(k^i^)

(c) 48k^

(d) 48(i^+j^)

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Answer:

Correct Answer: 1. (c)

Solution:

  1. Position of particle is, r=2ti^3t2j^

where, t is instantaneous time.

Velocity of particle is

v=drdt=2i^6t^j

Now, angular momentum of particle with respect to origin is given by

L=m(r×v)=m(2ti^3t2j^)×(2i^6tj^)

As, i^×i^=j^×j^=0

L=m(12t2k^+6t2k^)

As, i^×j^=k^ and j^×i^=k^

L=m(6t2)k^

So, angular momentum of particle of mass 2kg at time t=2s is

L=(2×6×22)k^=48k^



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