Optics 6 Question 36
38. In a Young’s double slit experiment, the separation between the two slits is $d$ and the wavelength of the light is $\lambda$. The intensity of light falling on slit 1 is four times the intensity of light falling on slit 2 . Choose the correct choice (s).
$(2008,4 M)$
(a) If $d=\lambda$, the screen will contain only one maximum
(b) If $\lambda<d<2 \lambda$, at least one more maximum (besides the central maximum) will be observed on the screen
(c) If the intensity of light falling on slit 1 is reduced so that it becomes equal to that of slit 2 , the intensities of the observed dark and bright fringes will increase
(d) If the intensity of light falling on slit 2 is increased so that it becomes equal to that of slit 1 , the intensities of the observed dark and bright fringes will increase
Show Answer
Solution:
- For $d=\lambda$, there will be only one, central maxima.
For $\lambda<d<2 \lambda$, there will be three maximas on the screen corresponding to path difference, $\Delta x=0$ and $\Delta x= \pm \lambda$.
