Optics 3 Question 35

35. An object is approaching a thin convex lens of focal length 0.3m with a speed of 0.01m/s. Find the magnitudes of the rates of change of position and lateral magnification of image when the object is at a distance of 0.4m from the lens.

(2004, 4M)

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Answer:

Correct Answer: 35. 0.09m/s,0.3/s

Solution:

  1. Differentiating the lens formula 1v1u=1f with respect to time, we get

1v2dvdt+1u2dudt=0 (as f= constant) dvdt=v2u2dudt

Further, substituting proper values in lens formula, we have

or

1v+10.4=10.3(u=0.4m,f=0.3m)v=1.2m

Putting the values in Eq. (i), we get

Magnitude of rate of change of position of image =0.09m/s

Lateral magnification, m=vu

dmdt=udvdtvdudtu2=(0.4)(0.09)(1.2)(0.01)(0.4)2=0.3/s

Magnitude of rate of change of lateral magnification

=0.3/s



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