Optics 2 Question 3

3. In figure, the optical fibre is l=2m long and has a diameter of d=20μm. If a ray of light is incident on one end of the fibre at angle θ1=40, the number of reflections it makes before emerging from the other end is close to (refractive index of fibre is 1.31 and sin40=0.64 )

(Main 2019, 8 April I)

(a) 55000

(b) 66000

(c) 45000

(d) 57000

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Answer:

Correct Answer: 3. (d)

Solution:

  1. Total internal reflection occurs through given glass rod as shown in figure.

From Snell’s law, n1sini=n2sinr

where, n1=1,n2=1.31 and i=40

So, we get

1sin40=1.31sinrsinr=0.641.31=0.490.5

So, r=30

From OAB,θ=90r=60

Now, tanθ=x20μm

x=203μm[tan60=3]

One reflection occurs in 203μm.

Total number of reflections occurring in 2m

=n=2m203μm=2203×106=57735 reflections 57000 reflections 



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