Optics 2 Question 14

14. A spherical surface of radius of curvature R, separates air (refractive index 1.0) from glass (refractive index 1.5). The centre of curvature is in the glass. A point object P placed in air is found to have a real image Q in the glass. The line PQ cuts the surface at a point O and PO=OQ. The distance PO is equal to

(1998,2M)

(a) 5R

(b) 3R

(c) 2R

(d) 1.5R

Show Answer

Answer:

Correct Answer: 14. (a)

Solution:

  1. Let us say PO=OQ=X

Applying

μ2v−μ1u=μ2−μ1R

Substituting the values with sign

1.5+X−1.0−X=1.5−1.0+R

(Distances are measured from O and are taken as positive in the direction of ray of light)

∴2.5X=0.5R∴X=5R

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