Modern Physics 5 Question 27
30. The binding energies per nucleon for deuteron $\left({ } _1 H^{2}\right)$ and helium $\left({ } _2 He^{4}\right)$ are $1.1 MeV$ and $7.0 MeV$ respectively. The energy released when two deuterons fuse to form a helium nucleus $\left({ } _2 He^{4}\right)$ is
$(1988,2 M)$
True/False
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Answer:
Correct Answer: 30. (a) 232,90 (b) $5.3 MeV, 1823.2 MeV$
Solution:
- $2{ } _1 H^{2} \rightarrow{ } _2 He^{4}$
Binding energy of two deuterons,
$$ E _1=2[2 \times 1.1]=4.4 MeV $$
Binding energy of helium nucleus,
$$ \begin{aligned} E _2 & =4(7.0)=28.0 MeV \\ \therefore \quad \text { Energy released } \Delta E & =E _2-E _1 \\ & =(28-4.4) MeV=23.6 MeV \end{aligned} $$
