Magnetics 6 Question 15

15. Two very long straight parallel wires carry steady currents I and −I respectively. The distance between the wires is d. At a certain instant of time, a point charge q is at a point equidistant from the two wires in the plane of the wires. Its instantaneous velocity v is perpendicular to this plane. The magnitude of the force due to the magnetic field acting on the charge at this instant is

(1998, 2M)

(a) μ0Iqv2πd

(b) μ0Iqvπd

(c) 2μ0Iqvπd

(d) zero

Objective Questions II (One or more correct option)

Show Answer

Solution:

  1. Net magnetic field due to both the wires will be downward as shown in the figure.

Since, angle between v and B is 180∘.

Therefore, magnetic force

Fm=q(v×B)=0

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