Magnetics 5 Question 4

4. A paramagnetic substance in the form of a cube with sides 1 cm has a magnetic dipole moment of 20×106J/T when a magnetic intensity of 60×103A/m is applied. Its magnetic susceptibility is

(2019 Main, 11 Jan II)

(b) The atom is placed in a uniform magnetic induction B such that the normal to the plane of electron’s orbit makes an angle of 30 with the magnetic induction. Find the torque experienced by the orbiting electron.

(a) 3.3×104

(b) 3.3×102

(c) 4.3×102

(d) 2.3×102

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Answer:

Correct Answer: 4. (a)

Solution:

  1. Given, side of cube =1cm=102m

Volume, V=106m3

Dipole moment, M=20×106J/T

Applied magnetic intensity, H=60×103A/m

Intensity of magnetisation

I=MV=20×106106=20A/m

Now, magnetic susceptibility χ is

χ= Intensity of magnetisation  Applied magnetic intensity =IH=2060×103

χ=13×103=3.33×104



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