SATHEE: Magnetics 4 Question 4

Magnetics 4 Question 4

5. The dipole moment of a circular loop carrying a current $I$ is $m$ and the magnetic field at the centre of the loop is $B_{1}$ . When the dipole moment is doubled by keeping the current constant, the magnetic field at the centre of the loop is $B_{2}$ . The ratio $\frac{B_{1}}{B_{2}}$ is

(2018 Main)

(a) $\frac{1}{\sqrt{2}}$

(b) 2

(d) $\sqrt{2}$

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Answer:

Correct Answer: 5. (d)

Solution:

$m = I \times π R^{2}$

$\begin{aligned} 2 m = I \times π {(R^{'})}^{2} \Rightarrow R^{'} = \sqrt{2} R \\ B = \frac{μ_{0} I}{2 π R} \Rightarrow B \propto \frac{1}{R} \Rightarrow \frac{B_{1}}{B_{2}} = \frac{R^{'}}{R} = \sqrt{2} \end{aligned}$

Magnetics 4 Question 4

5. The dipole moment of a circular loop carrying a current $I$ is $m$ and the magnetic field at the centre of the loop is $B_{1}$ . When the dipole moment is doubled by keeping the current constant, the magnetic field at the centre of the loop is $B_{2}$ . The ratio $\frac{B_{1}}{B_{2}}$ is

Answer:

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Magnetics 4 Question 4

5. The dipole moment of a circular loop carrying a current I is m and the magnetic field at the centre of the loop is B1. When the dipole moment is doubled by keeping the current constant, the magnetic field at the centre of the loop is B2. The ratio B1B2 is

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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5. The dipole moment of a circular loop carrying a current $I$ is $m$ and the magnetic field at the centre of the loop is $B_{1}$ . When the dipole moment is doubled by keeping the current constant, the magnetic field at the centre of the loop is $B_{2}$ . The ratio $\frac{B_{1}}{B_{2}}$ is