Magnetics 1 Question 26
26. In which case will the particle move in a straight line with constant velocity?
(a) (II) (iii) (S)
(b) (III) (iii) (P)
(c) (IV) (i) (S)
(d) (III) (ii) (R)
Show Answer
Answer:
Correct Answer: 26. $D, B$
Solution:
- $\quad \mathbf{F} _{\text {net }}=\mathbf{F} _e+\mathbf{F} _B=q \mathbf{E}+q \mathbf{v} \times \mathbf{B}$
For particle to move in straight line with constant velocity, $\mathbf{F} _{\text {net }}=0$
$\therefore q \mathbf{E}+q \mathbf{v} \times \mathbf{B}=0$
