Magnetics 1 Question 24

24. A proton moving with a constant velocity passes through a region of space without any change in its velocity. If E and B represent the electric and magnetic fields respectively. Then, this region of space may have

(1985,2M)

(a) E=0,B=0

(b) E=0,B0

(c) E0,B=0

(d) E0,B0

Match the Columns

Directions (Q.Nos. 25-27) Matching the information given in the three columns of the following table.

A charged particle (electron or proton) is introduced at the origin (x=0,y=0,z=0) with a given initial velocity v. A uniform electric field E and a uniform magnetic field B exist everywhere. The velocity v, electric field E and magnetic field B are given in columns 1, 2 and 3, respectively. The quantities E0,B0 are positive in magnitude.

Column 1 Column 2 Column 3
(l) Electron with
v=2E0B0x^
(i) E=E0z^ (P) B=B0x^
(II) Election with
v=E0B0y^
(ii) E=E0y^ (Q) B=B0x^
(III) Proton with
v=0
(iii) E=E0x^ (R) B=B0y^
(IV) Proton with
v=2E0B0x^
(iv) E=E0x^ (S) B=B0z^

(2017 Adv.)

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Answer:

Correct Answer: 24. (a,b,d)

Solution:

  1. If both E and B are zero, then Fe and Fm both are zero. Hence, velocity may remain constant. Therefore, option (a) is correct.

If E=0,B0 but velocity is parallel or antiparallel to magnetic field, then also Fe and Fm both are zero. Hence, option (b) is also correct.

If E0,B0 but Fe+Fm=0, then also velocity may remain constant or option (d) is also correct.



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