Laws of Motion 4 Question 8
8. A simple pendulum with a bob of mass $m$ swings with an angular amplitude of $40^{\circ}$. When its angular displacement is $20^{\circ}$, the tension in the string is greater than $m g \cos 20^{\circ}$.
$(1984,2 \mathrm{M})$
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Answer:
Correct Answer: 8. $\mathrm{T}$
Solution:
- $T-m g \cos 20^{\circ}=\frac{m v^{2}}{R}$ or $T=m g \cos 20^{\circ}+\frac{m v^{2}}{R}$
