Laws of Motion 3 Question 12
12. A block of mass $0.1 kg$ is held against a wall applying a horizontal force of $5 N$ on the block. If the coefficient of friction between the block and the wall is 0.5 , the magnitude of the frictional force acting on the block is
(1994, 1M)
(a) $2.5 N$
(b) $0.98 N$
(c) $4.9 N$
(d) $0.49 N$
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Answer:
Correct Answer: 12. (b)
Solution:
- $N=5 N$
$(f) _{\max }=\mu N=(0.5)(5)=2.5 N$
For vertical equilibrium of the block,
$f=m g=0.98 N<(f) _{\max }$
