SATHEE: Laws of Motion 3 Question 12

Laws of Motion 3 Question 12

12. A block of mass $0.1 k g$ is held against a wall applying a horizontal force of $5 N$ on the block. If the coefficient of friction between the block and the wall is 0.5 , the magnitude of the frictional force acting on the block is

(1994, 1M)

(a) $2.5 N$

(b) $0.98 N$

(d) $0.49 N$

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Answer:

Correct Answer: 12. (b)

Solution:

$N = 5 N$

$(f)_{max} = μ N = (0.5) (5) = 2.5 N$

For vertical equilibrium of the block,

$f = m g = 0.98 N < (f)_{max}$

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Laws of Motion 3 Question 12

12. A block of mass 0.1kg is held against a wall applying a horizontal force of 5N on the block. If the coefficient of friction between the block and the wall is 0.5 , the magnitude of the frictional force acting on the block is

Answer:

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12. A block of mass $0.1 k g$ is held against a wall applying a horizontal force of $5 N$ on the block. If the coefficient of friction between the block and the wall is 0.5 , the magnitude of the frictional force acting on the block is