SATHEE: Heat and Thermodynamics 1 Question 21

Heat and Thermodynamics 1 Question 21

21. $300 g$ of water at $25^{\circ} C$ is added to $100 g$ of ice at $0^{\circ} C$ . The final temperature of the mixture is.. $^{\circ} C$ .

$(1989, 2 M)$

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Solution:

Heat liberated when $300 g$ water at $25^{\circ} C$ goes to water at $0^{\circ} C : Q = m s Δ θ = (300) (1) (25) = 7500 c a l$

From $Q = m L$ , this much heat can melt mass of ice given by

$m = \frac{Q}{L} = \frac{7500}{80} = 93.75 g$

i.e. whole ice will not melt.

Hence, the mixture will be at $0^{\circ} C$ .

Mass of water in mixture

$\begin{aligned} = 300 + 93.75 \\ = 393.75 g and \end{aligned}$

Mass of ice in mixture

$= 100 - 93.75 = 6.25 g$

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Heat and Thermodynamics 1 Question 21

21. 300g of water at 25∘C is added to 100g of ice at 0∘C. The final temperature of the mixture is..∘C.

Solution:

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21. $300 g$ of water at $25^{\circ} C$ is added to $100 g$ of ice at $0^{\circ} C$ . The final temperature of the mixture is.. $^{\circ} C$ .