SATHEE: General Physics Question 19

General Physics Question 19

Question 19

The pitch of a screw gauge is $1 mm$ and there are 100 divisions on the circular scale. While measuring the diameter of a wire, the linear scale reads $1 mm$ and 47th division on the circular scale coincides with the reference line. The length of the wire is $5.6 cm$ . Find the curved surface area $($ in $^{2}$ ) of the wire in appropriate number of significant figures.

(2004, 2M)

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Answer:

Correct Answer: 20. $(2.6 {cm}^{2})$

Solution:

Least count of screw gauge $= \frac{1 mm}{100} = 0.01 mm$

Diameter of wire $= (1 + 47 \times 0.01) mm = 1.47 mm$

Curved surface area $($ in ${cm}^{2}) = (2 π) \frac{d}{2} (L)$

$\begin{aligned} S & = π d L = (π) (1.47 \times 10^{- 1}) (5.6) {cm}^{2} & = 2.5848 {cm}^{2} \end{aligned}$

Rounding off to two significant digits

$S = 2.6 {cm}^{2}$

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General Physics Question 19

Question 19

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