SATHEE: General Physics Question 16

General Physics Question 16

Question 16

A steel wire of diameter $0.5 mm$ and Young’s modulus $2 \times 10^{11} N m^{- 2}$ carries a load of mass $m$ . The length of the wire with the load is $1.0 m$ . A vernier scale with 10 divisions is attached to the end of this wire. Next to the steel wire is a reference wire to which a main scale, of least count $1.0 mm$ , is attached. The 10 divisions of the vernier scale correspond to 9 divisions of the main scale. Initially, the zero of vernier scale coincides with the zero of main scale. If the load on the steel wire is increased by $1.2 kg$ , the vernier scale division which coincides with a main scale division is . (Take, $g = 10 {ms}^{- 2}$ and $π = 3.2$ ).

(2018 Adv.)

Integer Answer Type Question

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Answer:

Correct Answer: 17. (3)

Solution:

Given, $d = 0.5 mm$ ,

$\begin{aligned} Y & = 2 \times 10^{11} {Nm}^{- 2} l & = 1 m Δ l & = \frac{F l}{A Y} = \frac{m g l}{\frac{π d^{2}}{4} Y} = \frac{1.2 \times 10 \times 1}{\frac{π}{4} \times {(5 \times 10^{- 4})}^{2} \times 2 \times 10^{11}} & = 0.3 mm \end{aligned}$

$LC$ of vernier $= 1 - \frac{9}{10} mm = 0.1 mm$

So, 3rd division of vernier scale will coincide with main scale.

General Physics Question 16

Question 16

Integer Answer Type Question

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General Physics Question 16

Question 16

Integer Answer Type Question

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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