SATHEE: Electrostatics 7 Question 20

Electrostatics 7 Question 20

22. Two non-conducting solid spheres of radii $R$ and $2 R$ , having uniform volume charge densities $ρ_{1}$ and $ρ_{2}$ respectively, touch each other. The net electric field at a distance $2 R$ from the centre of the smaller sphere, along the line joining the centre of the spheres, is zero. The ratio $ρ_{1} / ρ_{2}$ can be

(2013 Adv.)

(a) -4

(b) $\frac{- 32}{25}$

(d) 4

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Answer:

Correct Answer: 22. (b,d)

Solution:

At point $P$

If resultant electric field is zero, then

$\frac{K Q_{1}}{4 R^{2}} = \frac{K Q_{2}}{8 R^{3}} R \Rightarrow \frac{ρ_{1}}{ρ_{2}} = 4$

At point $Q$

If resultant electric field is zero then

$\begin{aligned} \frac{K Q_{1}}{4 R^{2}} + \frac{K Q_{2}}{25 R^{2}} & = 0 \\ \frac{ρ_{1}}{ρ_{2}} & = - \frac{32}{25} (ρ_{1} must be negative) \end{aligned}$

Electrostatics 7 Question 20

Answer:

Solution:

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Electrostatics 7 Question 20

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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