SATHEE: Electrostatics 5 Question 44

Electrostatics 5 Question 44

46. Five identical capacitor plates, each of area $A$ , are arranged such that adjacent plates are at a distance $d$ apart, the plates are connected to a source of emf $V$ as shown in the figure.

(1984, 2M)

The charge on plate 1 is and on plate 4 is ……

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Answer:

Correct Answer: 46. $\frac{ε_{0} A V}{d}, - \frac{2 ε_{0} A V}{d}$

Solution:

In the circuit shown in figure, there is a capacitor between plates 1 and 2 , the capacity of which is : $C_{1} = \frac{ε_{0} A}{d}$ and potential difference between its plates is $V$ . Therefore, charge stored in it is, $q = C_{1} V = \frac{ε_{0} A V}{d}$

Since, plate 1 is connected with positive terminal, hence this charge $q$ will be positive.

Plate 4 is making two capacitors, one with 3 and other with 5.

Hence, charge on it will be $- 2 q$ or $\frac{- 2 ε_{0} A V}{d}$ . Charge on it is negative because this is connected with negative plate. Charges on both sides of the plates are shown below.

Here,

$q = \frac{ε_{0} A V}{d}$

Electrostatics 5 Question 44

46. Five identical capacitor plates, each of area $A$ , are arranged such that adjacent plates are at a distance $d$ apart, the plates are connected to a source of emf $V$ as shown in the figure.

Answer:

Solution:

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Electrostatics 5 Question 44

46. Five identical capacitor plates, each of area A, are arranged such that adjacent plates are at a distance d apart, the plates are connected to a source of emf V as shown in the figure.

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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46. Five identical capacitor plates, each of area $A$ , are arranged such that adjacent plates are at a distance $d$ apart, the plates are connected to a source of emf $V$ as shown in the figure.