SATHEE: Electrostatics 5 Question 36

Electrostatics 5 Question 36

38. In the circuit shown in the figure, there are two parallel plate capacitors each of capacitance $C$ . The switch $S_{1}$ is pressed first to fully charge the capacitor $C_{1}$ and then released. The switch $S_{2}$ is then pressed to charge the capacitor $C_{2}$ . After some time, $S_{2}$ is released and then $S_{3}$ is pressed. After some time

(2013 Adv.)

(a) the charge on the upper plate of $C_{1}$ is $2 C V_{0}$

(b) the charge on the upper plate of $C_{1}$ is $C V_{0}$

(d) the charge on the upper plate of $C_{2}$ is $- C V_{0}$

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Answer:

Correct Answer: 38. (b,d)

Solution:

After pressing $S_{1}$ charge on upper plate of $C_{1}$ is $+ 2 C V_{0}$ .

After pressing $S_{2}$ this charge equally distributes in two capacitors. Therefore, charge an upper plates of both capacitors will be $+ C V_{0}$ .

When $S_{2}$ is released and $S_{3}$ is pressed, charge on upper plate of $C_{1}$ remains unchanged $(= + C V_{0})$ but charge on upper plate of $C_{2}$ is according to new battery $(= - C V_{0})$ .

Electrostatics 5 Question 36

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Electrostatics 5 Question 36

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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