Electrostatics 5 Question 15

17. A parallel plate capacitor is made of two square plates of side ’ a ’ separated by a distance d(d«a). The lower triangular portions is filled with a dielectric of dielectric constant k, as shown in the figure. Capacitance of this capacitor is

(Main 2019, 9 Jan I)

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(a) Kε0a2dlnK

(b) Kε0a2d(K1)lnK

(c) Kε0a22d(K+1)

(d) 12Kε0a2d

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Answer:

Correct Answer: 17. (b)

Solution:

  1. Let’s consider a strip of thickness ’ dx ’ at a distance of ’ x ’ from the left end as shown in the figure. From the figure, ABC and ADE are similar triangles,

yx=day=dax

We know that, the capacitance of parallel plate capacitor,

C=ε0AdC1=ε0(adx)(dy) and C2=Kε0(adx)y

Here, two capacitor are placed in series with variable thickness, therefore

Ceq=C1C2C1+C2Ceq=Kε0adxKd+(1K)y

Now, integrate it from 0 to a

C=0aKε0adxKd+(1K)y

Using Eq. (i), y=dax, we get

C=ε0a0adxd+1K1daxC=ε0a1KKdaln1KC=ε0a2KlnK(K1)d



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