Electrostatics 3 Question 17

17. A spherical metal shell A of radius RA and a solid metal sphere B of radius RB(<RA) are kept far apart and each is given charge +Q. Now they are connected by a thin metal wire. Then

(a) EAinside =0

(b) QA>QB

(c) σAσB=RBRA

(d) EAon surface <EBon surface 

(2011)

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Answer:

Correct Answer: 17. (a, b, c, d)

Solution:

  1. Inside a conducting shell electric field is always zero. Therefore, option (a) is correct. When the two are connected, their potentials become the same.

VA=VB or QARA=QBRBV=14πε0QR

Since, RA>RBQA>QB

Option (b) is correct.

Potential is also equal to, V=σRε0,VA=VB

σARA=σBRB or σAσB=RBRA or σA<σB

Option (c) is correct.

Electric field on surface, E=σε0 or Eσ

Since, σA<σBEA<EB

Option (d) is also correct

Correct options are (a), (b), (c) and (d).



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