Electrostatics 2 Question 25

26. Eight point charges are placed at the corners of a cube of edge $a$ as shown in figure. Find the work done in disassembling this system of charges.

$(2003,2 \mathrm{M})$

Show Answer

Answer:

Correct Answer: 26. $W=5.824 \Big[\frac{1}{4 \pi \varepsilon_{0}} \cdot \frac{q^{2}}{a}\Big]$

Solution:

  1. For potential energy of the system of charges, total number of charge pairs will be ${ }^{8} C_{2}$ or 28 of these 28 pairs 12 unlike charges are at a separation $a, 12$ like charges are at separation $\sqrt{2} a$ and 4 unlike charges are at separation $\sqrt{3} a$. Therefore, the potential energy of the system is given as

$$ \begin{aligned} U & =\frac{1}{4 \pi \varepsilon_{0}} \Big[\frac{(12)(q)(-q)}{a}+\frac{(12)(q)(q)}{\sqrt{2} a}+\frac{(4)(q)(-q)}{\sqrt{3} a}\Big] \\ & =-5.824 \Big[\frac{1}{4 \pi \varepsilon_{0}} \cdot \frac{q^{2}}{a}\Big] \end{aligned} $$

The binding energy of this system is therefore,

$$ |U|=5.824 \Big[\frac{1}{4 \pi \varepsilon_{0}} \frac{q^{2}}{a}\Big] $$

So, work done by external forces in disassembling, this system of charges is $W=5.824 \Big[\frac{1}{4 \pi \varepsilon_{0}} \cdot \frac{q^{2}}{a}\Big]$



NCERT Chapter Video Solution

Dual Pane