Electrostatics 2 Question 21

22. The electric potential $V$ at any point $x, y, z$ (all in metre) in space is given by $V=4 x^{2}$ volt. The electric field at the point $(1 \mathrm{~m}, 0,2 \mathrm{~m})$ is ….. V/m.

(1992, 1M)

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Answer:

Correct Answer: 22. $-8 \hat{\mathbf{i}}$

Solution:

  1. $\quad \mathbf{E}=-\frac{\partial V}{\partial x} \hat{\mathbf{i}}+\frac{\partial V}{\partial y} \hat{\mathbf{j}}+\frac{\partial V}{\partial z} \hat{\mathbf{k}} \Rightarrow V=4 x^{2}$

Therefore, $\frac{\partial V}{\partial x}=8 x$ and $\frac{\partial V}{\partial y}=0=\frac{\partial V}{\partial z}$

$$ \mathbf{E}=-8 x \hat{\mathbf{i}} $$

or $\mathbf{E}$ at $(1 \mathrm{~m}, 0,2 \mathrm{~m})$ is $-8 \hat{\mathbf{i}} \mathrm{V} / \mathrm{m}$



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