Electrostatics 2 Question 13

14. Three charges Q,+q and +q are placed at the vertices of a right angle triangle (isosceles triangle) as shown. The net electrostatic energy of the configuration is zero, if Q is equal to

(2000,2M)

(a) −q1+2

(b) −2q2+2

(c) −2q

(d) +q

Show Answer

Answer:

Correct Answer: 14. (b)

Solution:

  1. Net electrostatic energy of the configuration will be

U=Kq⋅qa+Q⋅q2a+Q⋅qa

Here, K=14πε0

Putting U=0 we get, Q=−2q2+2

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