Electrostatics 2 Question 12

13. A uniform electric field pointing in positive $x$-direction exists in a region. Let $A$ be the origin, $B$ be the point on the $x$-axis at $x=+1 \mathrm{~cm}$ and $C$ be the point on the $y$-axis at $y=+1 \mathrm{~cm}$. Then the potentials at the points $A, B$ and $C$ satisfy

$(2001,1 \mathrm{M})$

(a) $V_{A}<V_{B}$

(b) $V_{A}>V_{B}$

(c) $V_{A}<V_{C}$

(d) $V_{A}>V_{C}$

Show Answer

Answer:

Correct Answer: 13. $(b)$

Solution:

  1. Potential decreases in the direction of electric field. Dotted lines are equipotential lines.

$$ \therefore \quad V_{A}=V_{C} \quad \text { and } \quad V_{A}>V_{B} $$



NCERT Chapter Video Solution

Dual Pane