Electromagnetic Induction and Alternating Current 7 Question 15

(a) EC=EDln2

(b) EC=ED

(c) EC=2ED

(d) EC=12ED

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Answer:

Correct Answer: 15. (b)

Solution:

  1. When switch is closed for a very long time capacitor will get fully charged and charge on capacitor will be q=CV

Energy stored in capacitor, EC=12CV2

Work done by a battery, W=Vq=VCV=CV2

Energy dissipated across resistance

ED=( work done by battery )( energy stored )

ED=CV212CV2=12CV2

From Eqs. (i) and (ii)

ED=EC



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