SATHEE: Electromagnetic Induction and Alternating Current 6 Question 12

Electromagnetic Induction and Alternating Current 6 Question 12

####12. A series $R - C$ circuit is connected to AC voltage source. Consider two cases; $(A)$ when $C$ is without a dielectric medium and $(B)$ when $C$ is filled with dielectric of constant 4. The current $I_{R}$ through the resistor and voltage $V_{C}$ across the capacitor are compared in the two cases. Which of the following is/are true?

(a) $I_{R}^{A} > I_{R}^{B}$

(b) $I_{R}^{A} < I_{R}^{B}$

(d) $V_{C}^{A} < V_{C}^{B}$

(2011)

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Answer:

Correct Answer: 12. (b, c)

Solution:

$Z = \sqrt{R^{2} + X_{C}^{2}} = \sqrt{R^{2} + {\frac{1}{ω C}}^{2}}$

In case (b), capacitance $C$ will be more. Therefore, impedence $Z$ will be less. Hence, current will be more.

Further, $V_{C} = \sqrt{V^{2} - V_{R}^{2}} = \sqrt{V^{2} - (I R)^{2}}$

In case (b), since current $I$ is more.

Therefore, $V_{C}$ will be less.

Electromagnetic Induction and Alternating Current 6 Question 12

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Electromagnetic Induction and Alternating Current 6 Question 12

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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